Integrand size = 22, antiderivative size = 103 \[ \int (d x)^m \left (c x^2\right )^{5/2} (a+b x)^2 \, dx=\frac {a^2 c^2 (d x)^{6+m} \sqrt {c x^2}}{d^6 (6+m) x}+\frac {2 a b c^2 (d x)^{7+m} \sqrt {c x^2}}{d^7 (7+m) x}+\frac {b^2 c^2 (d x)^{8+m} \sqrt {c x^2}}{d^8 (8+m) x} \]
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Time = 0.04 (sec) , antiderivative size = 103, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.136, Rules used = {15, 16, 45} \[ \int (d x)^m \left (c x^2\right )^{5/2} (a+b x)^2 \, dx=\frac {a^2 c^2 \sqrt {c x^2} (d x)^{m+6}}{d^6 (m+6) x}+\frac {2 a b c^2 \sqrt {c x^2} (d x)^{m+7}}{d^7 (m+7) x}+\frac {b^2 c^2 \sqrt {c x^2} (d x)^{m+8}}{d^8 (m+8) x} \]
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Rule 15
Rule 16
Rule 45
Rubi steps \begin{align*} \text {integral}& = \frac {\left (c^2 \sqrt {c x^2}\right ) \int x^5 (d x)^m (a+b x)^2 \, dx}{x} \\ & = \frac {\left (c^2 \sqrt {c x^2}\right ) \int (d x)^{5+m} (a+b x)^2 \, dx}{d^5 x} \\ & = \frac {\left (c^2 \sqrt {c x^2}\right ) \int \left (a^2 (d x)^{5+m}+\frac {2 a b (d x)^{6+m}}{d}+\frac {b^2 (d x)^{7+m}}{d^2}\right ) \, dx}{d^5 x} \\ & = \frac {a^2 c^2 (d x)^{6+m} \sqrt {c x^2}}{d^6 (6+m) x}+\frac {2 a b c^2 (d x)^{7+m} \sqrt {c x^2}}{d^7 (7+m) x}+\frac {b^2 c^2 (d x)^{8+m} \sqrt {c x^2}}{d^8 (8+m) x} \\ \end{align*}
Time = 0.06 (sec) , antiderivative size = 48, normalized size of antiderivative = 0.47 \[ \int (d x)^m \left (c x^2\right )^{5/2} (a+b x)^2 \, dx=x (d x)^m \left (c x^2\right )^{5/2} \left (\frac {a^2}{6+m}+\frac {2 a b x}{7+m}+\frac {b^2 x^2}{8+m}\right ) \]
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Time = 0.34 (sec) , antiderivative size = 95, normalized size of antiderivative = 0.92
method | result | size |
gosper | \(\frac {x \left (b^{2} m^{2} x^{2}+2 a b \,m^{2} x +13 m \,x^{2} b^{2}+a^{2} m^{2}+28 a b m x +42 b^{2} x^{2}+15 a^{2} m +96 a b x +56 a^{2}\right ) \left (d x \right )^{m} \left (c \,x^{2}\right )^{\frac {5}{2}}}{\left (8+m \right ) \left (7+m \right ) \left (6+m \right )}\) | \(95\) |
risch | \(\frac {c^{2} x^{5} \sqrt {c \,x^{2}}\, \left (b^{2} m^{2} x^{2}+2 a b \,m^{2} x +13 m \,x^{2} b^{2}+a^{2} m^{2}+28 a b m x +42 b^{2} x^{2}+15 a^{2} m +96 a b x +56 a^{2}\right ) \left (d x \right )^{m}}{\left (8+m \right ) \left (7+m \right ) \left (6+m \right )}\) | \(100\) |
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Time = 0.24 (sec) , antiderivative size = 123, normalized size of antiderivative = 1.19 \[ \int (d x)^m \left (c x^2\right )^{5/2} (a+b x)^2 \, dx=\frac {{\left ({\left (b^{2} c^{2} m^{2} + 13 \, b^{2} c^{2} m + 42 \, b^{2} c^{2}\right )} x^{7} + 2 \, {\left (a b c^{2} m^{2} + 14 \, a b c^{2} m + 48 \, a b c^{2}\right )} x^{6} + {\left (a^{2} c^{2} m^{2} + 15 \, a^{2} c^{2} m + 56 \, a^{2} c^{2}\right )} x^{5}\right )} \sqrt {c x^{2}} \left (d x\right )^{m}}{m^{3} + 21 \, m^{2} + 146 \, m + 336} \]
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Leaf count of result is larger than twice the leaf count of optimal. 495 vs. \(2 (92) = 184\).
Time = 12.09 (sec) , antiderivative size = 495, normalized size of antiderivative = 4.81 \[ \int (d x)^m \left (c x^2\right )^{5/2} (a+b x)^2 \, dx=\begin {cases} \frac {- \frac {a^{2} \left (c x^{2}\right )^{\frac {5}{2}}}{2 x^{7}} - \frac {2 a b \left (c x^{2}\right )^{\frac {5}{2}}}{x^{6}} + \frac {b^{2} \left (c x^{2}\right )^{\frac {5}{2}} \log {\left (x \right )}}{x^{5}}}{d^{8}} & \text {for}\: m = -8 \\\frac {- \frac {a^{2} \left (c x^{2}\right )^{\frac {5}{2}}}{x^{6}} + \frac {2 a b \left (c x^{2}\right )^{\frac {5}{2}} \log {\left (x \right )}}{x^{5}} + \frac {b^{2} \left (c x^{2}\right )^{\frac {5}{2}}}{x^{4}}}{d^{7}} & \text {for}\: m = -7 \\\frac {\frac {a^{2} \left (c x^{2}\right )^{\frac {5}{2}} \log {\left (x \right )}}{x^{5}} + \frac {2 a b \left (c x^{2}\right )^{\frac {5}{2}}}{x^{4}} + \frac {b^{2} \left (c x^{2}\right )^{\frac {5}{2}}}{2 x^{3}}}{d^{6}} & \text {for}\: m = -6 \\\frac {a^{2} m^{2} x \left (c x^{2}\right )^{\frac {5}{2}} \left (d x\right )^{m}}{m^{3} + 21 m^{2} + 146 m + 336} + \frac {15 a^{2} m x \left (c x^{2}\right )^{\frac {5}{2}} \left (d x\right )^{m}}{m^{3} + 21 m^{2} + 146 m + 336} + \frac {56 a^{2} x \left (c x^{2}\right )^{\frac {5}{2}} \left (d x\right )^{m}}{m^{3} + 21 m^{2} + 146 m + 336} + \frac {2 a b m^{2} x^{2} \left (c x^{2}\right )^{\frac {5}{2}} \left (d x\right )^{m}}{m^{3} + 21 m^{2} + 146 m + 336} + \frac {28 a b m x^{2} \left (c x^{2}\right )^{\frac {5}{2}} \left (d x\right )^{m}}{m^{3} + 21 m^{2} + 146 m + 336} + \frac {96 a b x^{2} \left (c x^{2}\right )^{\frac {5}{2}} \left (d x\right )^{m}}{m^{3} + 21 m^{2} + 146 m + 336} + \frac {b^{2} m^{2} x^{3} \left (c x^{2}\right )^{\frac {5}{2}} \left (d x\right )^{m}}{m^{3} + 21 m^{2} + 146 m + 336} + \frac {13 b^{2} m x^{3} \left (c x^{2}\right )^{\frac {5}{2}} \left (d x\right )^{m}}{m^{3} + 21 m^{2} + 146 m + 336} + \frac {42 b^{2} x^{3} \left (c x^{2}\right )^{\frac {5}{2}} \left (d x\right )^{m}}{m^{3} + 21 m^{2} + 146 m + 336} & \text {otherwise} \end {cases} \]
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Time = 0.25 (sec) , antiderivative size = 64, normalized size of antiderivative = 0.62 \[ \int (d x)^m \left (c x^2\right )^{5/2} (a+b x)^2 \, dx=\frac {b^{2} c^{\frac {5}{2}} d^{m} x^{8} x^{m}}{m + 8} + \frac {2 \, a b c^{\frac {5}{2}} d^{m} x^{7} x^{m}}{m + 7} + \frac {a^{2} c^{\frac {5}{2}} d^{m} x^{6} x^{m}}{m + 6} \]
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Exception generated. \[ \int (d x)^m \left (c x^2\right )^{5/2} (a+b x)^2 \, dx=\text {Exception raised: TypeError} \]
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Time = 0.37 (sec) , antiderivative size = 127, normalized size of antiderivative = 1.23 \[ \int (d x)^m \left (c x^2\right )^{5/2} (a+b x)^2 \, dx={\left (d\,x\right )}^m\,\left (\frac {a^2\,c^2\,x^5\,\sqrt {c\,x^2}\,\left (m^2+15\,m+56\right )}{m^3+21\,m^2+146\,m+336}+\frac {b^2\,c^2\,x^7\,\sqrt {c\,x^2}\,\left (m^2+13\,m+42\right )}{m^3+21\,m^2+146\,m+336}+\frac {2\,a\,b\,c^2\,x^6\,\sqrt {c\,x^2}\,\left (m^2+14\,m+48\right )}{m^3+21\,m^2+146\,m+336}\right ) \]
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